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drizzle lua 数据传递(ngx.location.capture)

2014-03-23 12:43:01 来源:ITJS.CN
经常使用PHP开发的WEB开发人员,刚刚转到NGINX+DRIZZLE开发环境,开始估计会遇到LUA如何获取DRIZZLE+MYSQL返回数据的问题,下面给出我的一些经验。

首先修改NGINX的配置文件

location /mysql {

set $name $1;

set_quote_sql_str $quote_name $name;

set $sql "SELECT * FROM crawl WHERE id=3";

drizzle_query $sql; drizzle_pass mysql; rds_json on;

}

curl localhost:8080/mysql 返回的结果:[{"id":3,"url_id":"100","url_type":"item","date":"0000-00-00","url":"http://item.taobao.com/item.htm?id=100","status":0,"failures":0,"start_date":0,"unit_id":54848}]

然后在后面加入:

location /lua{

content_by_lua '

local res = ngx.location.capture("/mysql")

ngx.say("data: " .. res.body)

';

}

curl localhost:8080/lua 返回的结果:data: [{"id":3,"url_id":"100","url_type":"item","date":"0000-00-00","url":"http://item.taobao.com/item.htm?id=100","status":0,"failures":0,"start_date":0,"unit_id":54848}]

最后大家也就都能猜到了

location /luafile {

content_by_lua_file /usr/local/openresty/nginx/html/test.lua;

}

test.lua

local res = ngx.location.capture("/mysql")

ngx.say("data: " .. res.body)

搞定:curl localhost:8080/luafile 返回的结果:data: [{"id":3,"url_id":"100","url_type":"item","date":"0000-00-00","url":"http://item.taobao.com/item.htm?id=100","status":0,"failures":0,"start_date":0,"unit_id":54848}]